Question 297760
As you wrote the problem (15n-2)*(2n^3-3n^2-4n-5)
the multiplication produces
30n^4-49n^3-54n^2-67n+10

10 n^4-19n^3-14n^2-17n+10 comes from (5n-2)*(2n^3-3n^2-4n-5)
10n4 - 19n3 - 26n2 - 33n - 7 has no factors
10n4 - 15n3 - 20n2 - 25n + 10 has 5 as a factor
4n3 - 6n2 + 8n + 10 has 2 as a factor
You might double check whether it is  15n-2 or  5n-2
For those of you wondering, there was a typo. It should have been 5n-2.