Question 297725
log(x+2) + log(x-1) =1


log[(x+2)(x-1)] =1


(x+2)(x-1)=10


x^2+x-2=10


x^2+x-12=0


(x+4)(x-3)=0


x+4=0 or x-3=0


x=-4 or x=3


Only answer is x=3