Question 35294
X^2+6x+5 
use x= -b +or - Square root of ( b^2 -4(ac)) OVER 2a 
plug in from the problem a= the x^2 term which is 1

                         b= the x term which is 6
                          
                         c= the no x term the number which is 5 
plug those in therefor -6 +or- square root of 36 - 4(1*5) / 2
                       -6 +/- square 36-20 / 2
                        -6 +/- square 16 /2 
                        -6 +/- 4/2
                       -6 +/- 2
                         -6-2= -8
                              or          
                         -6+2= -4