Question 297570


{{{(2x-5)^2=121}}} Start with the given equation.



{{{2x-5=""+-sqrt(121)}}} Take the square root of both sides.



{{{2x-5=sqrt(121)}}} or {{{2x-5=-sqrt(121)}}} Break up the "plus/minus" to form two equations.



{{{2x-5=11}}} or {{{2x-5=-11}}}  Take the square root of {{{121}}} to get {{{11}}}.



{{{2x=5+11}}} or {{{2x=5-11}}} Add {{{5}}} to both sides.



{{{2x=16}}} or {{{2x=-6}}} Combine like terms.



{{{x=8}}} or {{{x=-3}}} Divide both sides by {{{2}}} to isolate {{{x}}}.



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Answer:



So the solutions are {{{x=8}}} or {{{x=-3}}}.