Question 297418
Let {{{n}}}= the number
{{{n - 2*(1/n) = 1/(4n)}}}
Multiply both sides by {{{n}}}
{{{n^2 - 2 = 1/4}}}
Multiply both sides by {{{4}}}
{{{4n^2 - 8 = 1}}}
{{{4n^2 = 9}}}
{{{n^2 = 9/4}}}
Take the square root of both sides
{{{n = 3/2}}}
and
{{{n = -3/2}}}
check answer:
{{{n - 2*(1/n) = 1/(4n)}}}
{{{(-3/2) - 2*(1/(-3/2)) = 1/(4*(-3/2))}}}
Multiply both sides by {{{2}}}
{{{-3 - 4*(-2/3) = -1/3}}}
{{{-3 + 8/3 = -1/3}}}
{{{-9/3 + 8/3 = -1/3}}}
{{{-1/3 = -1/3}}}
OK