Question 297396
let's factor 
20x^2-27x-8=
We need factors of -160 which add to -27
we know we have 4x and 1

-32 and +5
factor 20 
5 and 4 and -8
factor -32 4 and -8
-32 +5=-27
-32 4 and -8
(4x+1)*(5x-8)
The width is 5x-8
We could also have divided 20x^2-27x-8
4x-1