Question 297122
Was there a question or did you just want a graph? 
Remember, ln is defined only when the argument is positive. 
{{{x^2-1>0}}}
{{{x^2>1}}}
So the domain of f(x), as shown below, is, 
({{{ -infinity }}} , {{{-1}}}) U ({{{1}}}, {{{infinity}}})
{{{ graph( 300, 300, -10, 10, -10, 10, ln(x^2-1)) }}}