Question 296984
2x^2-7xy+6y^2

for any quadratic equation to be solved 

multiply the coefficient of the first term and the third term

split the second term into two terms such that the product of the two co-efficients  of split terms  must be equal to the the product of the co-efficients of term 1 & term 3  and their sum must be equal to the second term.

2x^2 -4xy-3xy+6y^2

-4 -3 =-7

-4*-3=12

2x(x-2y)-3v(x-2y)

(x-2y)(2x-3y)