Question 297121
Call the consecutive integers {{{n}}} and {{{n+1}}}
given:
{{{(1/5)*(n + n + 1) = n - 22}}}
Multiply both sides by {{{5}}}
{{{2n + 1 = 5*(n - 22)}}}
{{{2n + 1 = 5n - 110}}}
{{{3n = 111}}}
{{{n = 37}}} answer
check:
{{{(1/5)*(n + n + 1) = n - 22}}}
{{{(1/5)*(74 + 1) = 37 - 22}}}
{{{75/5 = 15}}}
{{{75 = 75}}}
OK