Question 35210
we need to get a common denominator:


{{{ 3/(x+2) - x/(x-3) }}}
{{{ (3/(x+2))((x-3)/(x-3)) - (x/(x-3))((x+2)/(x+2)) }}}
{{{ (3(x-3))/((x+2)(x-3)) - (x)(x+2)/((x-3)(x+2)) }}}
{{{ (3(x-3) - (x)(x+2))/((x+2)(x-3)) }}}
{{{ (3x-9-x^2-2x)/((x+2)(x-3)) }}}
{{{ (-x^2+x-9)/((x+2)(x-3)) }}}


the numerator doesn't factorise easily, so leave it.


jon.