Question 297013
If $5000 is invested in an account that pays interest compounded continuously, how long will it take to grow to $11,300 at 5.5%? 
-----------------------------------
A(t) = Pe^(rt)
11,300 = 5000*e^(0.055t)
2.26 = e^(0.055t)
-----
Take the natural log to get:
0.055t = ln(2.26)
t = 14.8248...
----------------------
Cheers,
Stan H.