Question 296873
{{{121=11^2}}}
{{{49=7^2}}}
the middle sign is negative so this is a true square
{{{(11x-7)(11x+7)}}} so this is an easy factor, now set both to 0 and solve for x
{{{11x-7=0}}}
{{{11x=7}}}
{{{x=7/11}}}
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{{{11x+7=0}}}
{{{11x=-7}}}
{{{x=-7/11}}}