Question 296777
I assume that this is 3m^2 = 20-7m  so the first thing you must do is get it into standard form of ax^2 + bx + c = 0..to do that you must first add 7m to both sides then subtract 20 from both sides and you will end up with

3m^2+7m-20 = 0  ...now you can factor..use 4 and 5 for 20:

(3m-5)(m+4) = 0   ...now you can say

3m-5=0   then 3m=5   then m=5/3   and/or
m+4=0  then m= -4

go back and use each in the original equation...both work so the answer is both 
-4 and 5/3

Hope this helps