Question 296783
{{{f(x)=2x^2-3x}}} Start with the first function.



{{{f(g(x))=2(4x-1)^2-3(4x-1)}}} On the left side, replace 'x' with 'g(x)'. On the right side, replace each 'x' with {{{4x-1}}}. Note: we replaced 'x' with 'g(x)' which in this case is {{{g(x)=4x-1}}}



{{{f(g(x))=2(16x^2-8x+1)-3(4x-1)}}} FOIL



{{{f(g(x))=32x^2-16x+2-12x+3}}} Distribute.



{{{f(g(x))=32x^2-28x+5}}} Combine like terms.



So the answer is {{{f(g(x))=32x^2-28x+5}}}