Question 296693
{{{0<=(2x+3)/4<4}}} Start with the given compound in inequality.



{{{0*4<=2x+3<4*4}}} Multiply all sides by 4.



{{{0<=2x+3<16}}} Multiply.



{{{0-3<=2x<16-3}}} Subtract 3 from all sides.



{{{-3<=2x<13}}} Combine like terms.



{{{-3/2<=x<13/2}}} Divide all sides by 2 to isolate 'x'.



So the solution is {{{-3/2<=x<13/2}}} which in interval notation looks like <font size=8>[</font>*[Tex \LARGE -\frac{3}{2},\frac{13}{2}]<font size=8>)</font>