Question 296191
What is the cube root of 6561 x cubed y divided by ab squared?
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{{{(6561*x^3y/ab^2)^(1/3)}}}
{{{6561 = 3^8 }}} in case you don't know that
= {{{(3^6*3^2*x^3y/ab^2)^(1/3)}}}
= {{{9x(9y/ab^2)^(1/3)}}}
= {{{9x(9a^2by/a^3b^3)^(1/3)}}}
= {{{(9x/ab)*(9a^2by)^(1/3)}}}