Question 296153
4m^(2)+10m+3=0

Use the quadratic formula to find the solutions.  In this case, the values are a=4, b=10, and c=3.
m=(-b\~(b^(2)-4ac))/(2a) where am^(2)+bm+c=0

Substitute in the values of a=4, b=10, and c=3.
m=(-10\~((10)^(2)-4(4)(3)))/(2(4))

Simplify the section inside the radical.
m=(-10\2~(13))/(2(4))

Simplify the denominator of the quadratic formula.
m=(-10\2~(13))/(8)

Simplify the expression to solve for the + portion of the \.
m=(-5+~(13))/(4)

Simplify the expression to solve for the - portion of the \.
m=(-5-~(13))/(4)

The roots of the polynomial equation & 4m^(2)+10m+3=0.
m=(-5+~(13))/(4),(-5-~(13))/(4)_m<Z>APPR<z>-0.35,-2.15