Question 296099
how do you work out (3+root 6)squared
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The same as squaring any binomial.
{{{(a + b)^2 = a^2 + 2ab + b^2}}}
{{{(3 + sqrt(6))^2 = 3^2 + 2*3*sqrt(6) + (sqrt(6))^2}}}
= {{{9 + 6sqrt(6) + 6}}}
= {{{15 + 6sqrt(6)}}}