Question 295751
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Let *[tex \Large x] represent the amount invested at 8%.  Then, since the rest of his money was invested at 9%, the amount invested at 9% was *[tex \Large 9000\ -\ x]


The amount of money he earned on the 8% investment was then *[tex \Large 0.08x], and the amount of money he earned on the 9% investment was *[tex \Large 0.09(9000\ -\ x)].


Since the total amount that he earned was $770, you can say:


*[tex \LARGE \ \ \ \ \ \ \ \ \ \ 0.08x\ +\ 0.09(9000\ -\ x)\ =\ 770]


Now just solve for *[tex \Large x].


John
*[tex \LARGE e^{i\pi} + 1 = 0]
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