Question 295752
Distribute, carefully
{{{(w+g)(A)=w(A)+g(A)}}}
in this case {{{A=w^2-wg+g^2}}}
{{{(w+g)(w^2-wg+g^2)=w( w^2-wg+g^2)+g(w^2-wg+g^2)}}}
{{{(w+g)(w^2-wg+g^2)=(w^3-w^2g+wg^2)+(w^2g-wg^2+g^3)}}}
{{{(w+g)(w^2-wg+g^2)=w^3-w^2g+w^2g+wg^2-wg^2+g^3}}}
{{{(w+g)(w^2-wg+g^2)=w^3+g^3}}}