Question 295607
Note: We can write 17 as {{{16&2/2}}} since {{{16&2/2=16+2/2=16+1=17}}}


Using the note above, we can go from


<pre>
  17
-  8 1/2
---------
</pre>



to


<pre>
  16 2/2
-  8 1/2
---------
</pre>


Now just subtract the common parts. So {{{16-8=8}}} and {{{2/2-1/2=(2-1)/2=1/2}}} meaning that 


<pre>
  16 2/2
-  8 1/2
---------
   8 1/2
</pre>



So this also means that 


<pre>
  17
-  8 1/2
---------
   8 1/2
</pre>