Question 295507
First, get both equations into slope-intercept form to derive some points.
.
Line 1:
3x -2y = -6
-2y = -3x -6
y = (3/2)x + 3
.
Using this equation we can find to points to draw a line...
(0,3) = y-intercept
(-2,0) = x-intercept
.
Line 2:
-3x -y = -12
-y = 3x -12
y = -3x +12
.
Two points are:  (0,12) and (4,0).
.
{{{drawing(500,500,-5,15,-5,15,
grid(1),
graph(500,500,-5,15,-5,15,3/2*x+3,-3*x+12) )}}}
.
So, the solution is (2,6)