Question 34974
Solve {{{x^2-2x+5 = 0}}}, using the quadratic formula:{{{x=(-b+-sqrt(b^2-4ac))/2a}}}

{{{x = (-(-2)+-sqrt((-2)^2-4(1)(5)))/2(1)}}}
{{{x = (2+-sqrt(4-20))/2}}}
{{{x = 1+-sqrt(-16)/2}}}
{{{x = 1+-4sqrt(-1)/2}}}
{{{x = 1+2i}}} or {{{x = 1-2i}}}

The roots are complex (a + bi)