Question 295315
There is an easier method available. 
{{{log((3x-3))=log((x+1))+log((4))}}}
   {{{log((3x-3))=log((4(x+1)))}}}
      {{{3x-3=4(x+1)}}}
 {{{3x-3=4x+4}}}
{{{-x=7}}}
{{{x=-7}}}
However, since the log function only takes positive arguments,
{{{3x-3>0}}}
{{{3x>3}}}
{{{x>1}}}
The solution must be greater than 1. 
No solution.