Question 295199
We are dealing with a right triangle here.
The distance between them is the hypotenuse c
and the distances walked are the legs.
so we have 
slower =s 
faster =f and 
distance =c
c=6*s
f=3*s
s^2+f^2=c^2

We have three equations in three unknowns
By substitution we have one equation with one unknown.
s^2+(3*s)^2=(6*s)^2
s^2+9s*2=36s^2
10s^2=36s^2
The only possible solution is 0
Double check the word problem.
Something is odd about the way it says "6 times more than the distance traveled by the slower walker." It seems like there should be a number in there.