Question 295154
(4z^2+4z-80)/(z^2-11z+28)    Simplify

(4z^2+4z-80)
= 4z^2+20z-16z-80

=4z(z+5)-16(z+5)

=(4z-16)(z+5)

=4(z-4)(z+5)


(z^2-11z+28)

=z^2-4z-7z+28

=z(z-4)-7(z-4)

=(z-4)(z-7)

=(z-4)(z-7)

4(z-4)(z+5)/ (z-4)(z-7)

=4(z+5)/(z-7)