Question 295131
let the integers be x , x+1, x+2

x^2+(x+1)^2 +(x+2)^2=50

x^2+x^2+2x+1 + x^2+4x+4 =50

3x^2+6x+5=50

3x^2+6x-45=0

x^2+2x-15=0

x^2+5x-3x-15=0

x(x+5)-3(x+5)=0

(x+5)(x-3)=0

x=-5 or x=3


the numbers can be -5, -4, -3   OR  3 , 4 , 5 

Both the solutions satisfy the equation