Question 294997
x^2-y^2=3
2x+y=3  --> y = -2x + 3
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Sub for y into the 1st eqn:
{{{x^2 - (-2x+3)^2 = 3}}}
{{{-3x^2 + 12x - 9 = 3}}}
{{{3x^2 - 12x + 12 = 0}}}
{{{x^2 - 4x + 4 = 0}}}
{{{(x-2)^2 = 0}}}
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x = 2, y = -1