Question 294846
Do the numerator 1st:
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{{{2(x-1)/((x+1)*(x-1)) + 1/(2(x+1))}}}
= {{{2/(x+1) + 1/(2(x+1))}}}
= {{{4/(2(x+1)) + 1/(2(x+1))}}}
= {{{5/2(x+1)}}}
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Then the denominator:
{{{(1/(x+1)) - 1 = (1 - (x+1))/(x+1)}}}
= {{{-x/(x+1)}}}
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Cancel the (x+1) in both.
= {{{(5/2)/(-x/1)}}}
Invert the den and multiply
= {{{(5/2)*(-1/x) = -5/2x}}}
-5/2x