Question 294749
1.{{{2x+3y=8}}} 

2.{{{3x+2y=7}}}
From eq. 1,
{{{2x+3y=8}}}
{{{2x=8-3y}}}
{{{x=4-(3/2)y}}}
{{{3x=12-(9/2)y}}}
Now subsitute into eq.2,
{{{3x+2y=7}}}
{{{(12-(9/2)y)+2y=7}}}
{{{-(9/2)y+(4/2)y=-5}}}
{{{-(5/2)y=-5}}}
{{{highlight(y=2)}}}
Then you can use either equation to solve for x.
{{{2x+3y=8}}}
{{{2x+3(2)=8}}}
{{{2x+6=8}}}
{{{2x=2}}}
{{{highlight( x=1)}}}