Question 294547
x^(2)-4x-7=0
x=(-b\~(b^(2)-4ac))/(2a) 
x=(-(-4)\~((-4)^(2)-4(1)(-7)))/(2(1))
x=(4\~((-4)^(2)-4(1)(-7)))/(2(1))
x=(4\2~(11))/(2(1))
x=(4\2~(11))/(2)
x=(4+2~(11))/(2)
x=2+~(11)
x=(4-2~(11))/(2)
x=2-~(11)
The final answer is the combination of both solutions.
x=2+~(11),2-~(11)_x<Z>APPR<z>5.32,-1.32