Question 294422
You can factor the numerator,
{{{m^2-1=(m+1)(m-1)}}}
So then
{{{(m^2-1)/(m+1)^2=(cross(m+1)(m-1))/(m+1)^cross(2)}}}
{{{(m^2-1)/(m+1)^2=(m-1)/(m+1)}}}