Question 294342
log base 2(y+2)-log base 2(y-2)=1
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{{{log(2,(y+2)) - log(2,(y-2)) = 1}}}
{{{log(2,((y+2)/(y-2))) = 1}}}
(y+2)/(y-2) = 2
y+2 = 2y-4
2 = y-4
y = 6