Question 294276
two cars leave the same day one heading north and the other heading west. the first car travels at 25km/hr. in 1 hour the cars are 65km apart. how fast is the second car moving


The distances travelled by the two cars form a right triangle. After one hour the hypotenuse is 65 and one leg is 25. If the distance travelled by the second car is x then, by the Pythagorean Theorem, we have:

x^2 + 25^2 = 65^2
x^2 = 65^2 - 25^2
x^2 = 4225 - 625
x^2 = 3600
x = sqrt(3600)
x = 60