Question 293896
{{{ 2x^3-x^2-18x+9=0 }}} Start with the given equation



{{{ (2x^3-x^2)+(-18x+9)=0 }}} Pair off the terms into two groups



{{{ x^2(2x-1)+(-18x+9)=0 }}} Factor out the GCF {{{x^2}}} from the first group.



{{{ x^2(2x-1)-9(2x-1)=0 }}} Factor out the GCF {{{-9}}} from the second group. The goal is get a common term between the two groups.



{{{ (x^2-9)(2x-1)=0 }}} Factor out the GCF {{{2x-1}}} from the entire left side.



{{{ (x+3)(x-3)(2x-1)=0 }}} Factor {{{x^2-9}}} to get {{{(x+3)(x-3)}}} using the difference of squares formula.



I'll let you take it from here.