Question 293322
How do you solve this equation?
Log base 3 x + Log base 3 9 = 1
:
Addition of logs the same as multiply, so we can write it:
logb3(9x) = 1
:
Write the exponent equiv of logs
3^1 = 9x
:
9x = 3
x = {{{3/9}}} - {{{1/3}}}