Question 293309
What is the focus point of y= 1/4x^2+2? 
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Convert the equation to vertex form:
(1/4)(x^2) = y-2
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(x-2)^2 = 4(y-2)
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Vertex at (2,2)
Parabola opens up so focus is above the vertex.
4p = 4
p = 1
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Focus = (2,3)
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Cheers,
Stan H.
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