Question 293272
I need to solve for X over interval {0, 2pi)
4cos2x=sqrt3 
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cos(2x) = (1/4)sqrt(3)
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Take the arcos of each side to get:
2x = arcos[(sqrt(3)/4]
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2x = 64.34 degrees
x = 32.17 degrees
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Cheers,
Stan H.