Question 293257
# 1


First we must solve for y:


{{{5x-y=-1}}} Start with the given equation.



{{{-y=-1-5x}}} Subtract {{{5x}}} from both sides.



{{{-y=-5x-1}}} Rearrange the terms.



{{{y=(-5x-1)/(-1)}}} Divide both sides by {{{-1}}} to isolate y.



{{{y=((-5)/(-1))x+(-1)/(-1)}}} Break up the fraction.



{{{y=5x+1}}} Reduce.



Now replace 'y' with f(x) to get {{{f(x)=5x+1}}}



So the function is {{{f(x)=5x+1}}}


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# 2



Again, we must solve for y:



{{{2y+3x=2}}} Start with the given equation.



{{{2y=2-3x}}} Subtract {{{3x}}} from both sides.



{{{2y=-3x+2}}} Rearrange the terms.



{{{y=(-3x+2)/(2)}}} Divide both sides by {{{2}}} to isolate y.



{{{y=((-3)/(2))x+(2)/(2)}}} Break up the fraction.



{{{y=-(3/2)x+1}}} Reduce.



Now replace 'y' with f(x) to get {{{f(x)=-(3/2)x+1}}}



So the function is {{{f(x)=-(3/2)x+1}}}