Question 293259
I'm not sure how you got that answer (it's the correct answer) since your steps are incorrect. 


Let L = length and W = width



Recall that the perimeter of a rectangle is {{{P=2L+2W}}}. Since the length is 2 ft more than the width, we can say that {{{L=W+2}}}



{{{P=2L+2W}}} Start with the given equation.



{{{20=2(W+2)+2W}}} Plug in {{{P=20}}} and {{{L=W+2}}}



{{{20=2W+4+2W}}} Distribute.



{{{20=4W+4}}} Combine like terms.



{{{20-4=4W}}} Subtract 4 from both sides.



{{{16=4W}}} Combine like terms.



{{{16/4=W}}} Divide both sides by 4 to isolate W.



{{{4=W}}} Reduce.



So the width is {{{W=4}}} ft and the length is {{{L=W+2=4+2=6}}} ft