Question 293221
{{{Log[9](0.3) = x}}} Rewrite this in exponential form:{{{Log[b](y) = x}}}--->{{{b^x = y}}}
{{{9^x = 0.3}}} Now take the common log (base = 10) of both sides.
{{{Log[10](9^x) = Log[10](0.3)}}} Use you calculator to find these logs. First apply the power rule for logarithms to the left side.
{{{x*Log(9) = Log(0.3)}}} Divide both sides by {{{Log(9)}}}.
{{{x = (Log(0.3))/Log(9)}}} Use your calculator to find the logs.
{{{x = -0.547951637145}}}... Rounded to...
{{{highlight(x = -0.5)}}} This does not quite match your answer!