Question 293221
The main thing to remember is: LOGS ARE EXPONENTS
The other main thing is:
You have to know how to read this:
{{{y = log(9,.3)}}}
First of all, it's telling you that {{{y}}} is an exponent,
since it says "y = log(something)"
Then it tells you that when you raise the base {{{9}}} to
the exponent {{{y}}}, the result is {{{.3}}}
Putting all that together:
{{{y = 9^.3}}}
You can also express {{{9}}} as {{{3^2}}}
{{{y = (3^2)^.3}}}
The rule for this is to multiply the exponents
{{{y = 3^.6}}}
You can solve this on a calculator, or
take the log to the base {{{10}}} of both sides
{{{log(y) = .6*log(3)}}}
{{{log(y) = .6*.477}}}
{{{log(y) = .286}}}
{{{y = 10^.286 }}}
{{{y = 1.933}}}
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Actually,
{{{1/2 = log(9,3)}}}
and, as I showed,
{{{1.933 = log(9,.3)}}}