Question 293152
{{{18x^2-128}}} Start with the given expression.



{{{2(9x^2-64)}}} Factor out the GCF {{{2}}}.



{{{2(3x+8)(3x-8)}}} Now factor {{{9x^2-64}}} to get {{{(3x+8)(3x-8)}}} (use the difference of squares formula)



So {{{18x^2-128}}} factors to {{{2(3x+8)(3x-8)}}}



In other words, {{{18x^2-128=2(3x+8)(3x-8)}}}