Question 292944
This cannot be factored over the rational numbers since we can write {{{9x^2+4y^2}}} as {{{9x^2+0xy+4y^2}}} and there are no numbers that both multiply to {{{9*4=36}}} and add to 0.



However, this can be factored over the complex numbers to get {{{(3x+2yi)(3x-2yi)}}}



Chances are that you've never seen imaginary numbers, so this means that the answer is simply "the polynomial is prime"