Question 292696
1. Complete the square to put into vertex form.
 {{{2x^2 -x-3= 2(x^2 -(1/2)x)-3}}}
 {{{2x^2 -x-3= 2(x^2 -(1/2)x+(1/16))-3-(1/8)}}}
{{{2x^2 -x-3= 2(x-1/4)^2-(25/8)}}}
{{{A=2}}}
{{{B=-1/4}}}
{{{C=-25/8}}}
2. From vertex form, the min occurs at the vertex {{{x=1/4}}}.
{{{ymin=-25/8}}}
{{{ graph( 300, 300, -5, 5, -10, 10, 2x^2 -x-3, 2(x-1/4)^2-(25/8)) }}}