Question 292823
This can be solved in several ways, I prefer the distance formula, which is 
sqrt((x2-x1)^2 + (y2-y1)^2)
Used in this problem, you would do this:
x2=5 and x1=-2 so 5+2=7 and 7^2= 49
y2=3 and y1=-1 so 3+1=4 and 4^2= 16
add 49 and 16 and get 55
the distance is sqrt(55)
which equals 7.416