Question 292738


{{{6x-3y=18}}} Start with the given equation.



{{{-3y=18-6x}}} Subtract {{{6x}}} from both sides.



{{{-3y=-6x+18}}} Rearrange the terms.



{{{y=(-6x+18)/(-3)}}} Divide both sides by {{{-3}}} to isolate y.



{{{y=((-6)/(-3))x+(18)/(-3)}}} Break up the fraction.



{{{y=2x-6}}} Reduce.



So the equation {{{y=2x-6}}} is now in slope intercept form {{{y=mx+b}}} where the slope is {{{m=2}}} and the y-intercept is {{{b=-6}}} note: the y-intercept is the point *[Tex \LARGE \left(0,-6\right)]