Question 292003
A rock is thrown upward from the top of a 250-foot cliff with a velocity of 14 feet per second.
 The height, h, in feet of the object after t seconds is h = –16t^2 + 14t + 250.
 Approximately how long after the object is thrown will it strike the ground below?
:
Plot this equation:
{{{ graph( 300, 200, -2, 6, -100, 300, -16x^2+14x+250) }}}
:
Looks like it will strike the ground in 4.4 sec
:
If you want the exact time, use the quadratic formula to find the positive solution
a=-16; b=14; c=250 

:
Response to student comment:
I did use a TI83 to graph the equation, y = -16x^2+14x+250 with a scale:
Window: -2,6,1 and -100,300,20 to get the graph you see
:
But you can graph it on graph paper, by making a table and plotting the x,y points. If you want me to help you do that, my email ankor@att.net
:
What are you confused about? 
: