Question 292302
Use a(t) = -9.8 meters per second per second as the acceleration due to gravity. (Neglect air resistance.)
A baseball is thrown upward from a height of 3 meters with an initial velocity of 11 meters per second. Determine its maximum height. (Round your answer to two decimal places.)
:
The equation for this
h(x) = -9.8x^2 + 11x + 3
:
Find the axis of symmetry: x = -b/(2a)
x = {{{(-11)/(2*-9.8)}}}
x = {{{(-11)/(-19.6)}}}
x = +.561 secs is when max height occurs
:
Find the height, replace x with .561
h(x) = -9.8(.561^2) + 11(.561) + 3
h(x) = -9.8(.315) + 6.171 + 3
h(x) = -3.084 + 6.171 + 3
h(x) = 6.087 meters is max height