Question 292189
{{{5+sqrt(x)=15}}}
{{{sqrt(x)=10}}}
{{{x=100}}}
.
.
.
{{{2*sqrt(x+1)=sqrt(x-5)}}}
{{{4(x+1)=x-5}}}
{{{4x+4=x-5}}}
{{{3x=-9}}}
{{{x=-3}}}
Check your answer here. 
{{{2*sqrt(-3+1)=sqrt(-3-5)}}}
{{{2*sqrt(-2)=sqrt(-8)}}}
The solution is not valid because it leads to an undefined quantity. 
Only solutions where 
{{{x>=5}}} would be valid. 
There is no solution.